n^2-5n-50=(n+5)(n-)

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Solution for n^2-5n-50=(n+5)(n-) equation: 



n^2-5n-50=(n+5)(n-)

We move all terms to the left:

n^2-5n-50-((n+5)(n-))=0

We add all the numbers together, and all the variables

n^2-5n-((n+5)(+n))-50=0

We multiply parentheses ..

n^2-((+n^2+5n))-5n-50=0



We calculate terms in parentheses: -((+n^2+5n)), so:

(+n^2+5n)

We get rid of parentheses

n^2+5n

Back to the equation:

-(n^2+5n)



We add all the numbers together, and all the variables

n^2-5n-(n^2+5n)-50=0

We get rid of parentheses

n^2-n^2-5n-5n-50=0

We add all the numbers together, and all the variables

-10n-50=0

We move all terms containing n to the left, all other terms to the right

-10n=50

n=50/-10

n=-5

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